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Show that the points (3,-2) (-2,8) and (0.4) are collinear points. |
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Answer» A=(3,-2),B=(-2,8) C=(0,4) (if three POINTS A B C are collinear then the SLOP of AB=BC) slop of AB Y2 -Y1÷X2-X1 8-(-2)÷-2-3 =8+2÷(-5) = 10÷-5 = -2 slop of BC 4-8÷0--2 =4÷2 =2 |
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