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Show that the lengths of tangents drawn from an external point to a circle are equa |
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Answer» Hey!! Here is your answer..... Statement :- The lengths of tangents drawn from an external point to a circle are equal. Given :- A circle with centre o, p is a point lying outside the circle and PA and PB are two tangents to the circle from p. To PROVE :-PA=PB. Proof :- Join OA, OB and OP. ANGLE OBP = Angle OAP = 90
(Angle between tangent and radius is 90) Now in ∆OAP and in ∆OBP OA = OB(RADII of the same circle) OP=OP ∆OAP congruent ∆ OBP(R. H. S congruence) :. PA=PB ( CPCT) Hence proved. Hope it helps you.... Please mark it as brain liest answer...
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