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Show that the equation has exactly one real root: x^{3}+e^{x}=0 |
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Answer» Thank you but I was hoping to see this shown using Intermediate Value Theorem and Rolle's Theorem That i have used without mentioning it as it quite noticeable fact as f(x) is continuous and differentiable, there it is negitive for some value and positive fo some and as it is strictly increasing because f'(x) > 0so it cuts the x axis one time. that is exactly one zero. |
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