Saved Bookmarks
| 1. |
Show that the diagonals of a square are equal and bisect each other at right angles. |
|
Answer» Answer: given ABCD is a square prove AC = BD,OA=OC Step-by-step explanation: proof . in triangle BAD and CAD AD =AD(COMMON) AB = CO( sides of square ) angle C = angle A (each 90 DEGREE) by SAS rule triangle BAD is congruent to triangle hence, BO=AC (by CPCT) every square is parallelogram diagonal bisect each other = OA = OC, OB=OD in triangle ADB and triangle COB AB= CB OB=OB(COMMON) OA =OC (PROVED ABOVE) BY SSS RULE triangle ABC is congruent to triangle COB angle AOB +angle COB=180 DEGREE angle AOB+angle AOB=180 DEGREE twice of angle AOB =180 DEGREE angle AOB= 180/2=90 DEGREE THERE FORE, AOB=90 DEGREE HENCE, PROVED
|
|