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Show that tan 48' tan 16 tan42 tan 74=1 |
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Answer» Answer: given:- LHS=TAN 48 tan 16 tan42 tan 74 tan48 tan16 tan(90-42) tan(90-74) tan48 tan16 cot48 cot16 (SINCE tan(90-Ø) = cotØ) tan48cot48 tan16cot16 1×1 (since tanØcotØ = 1) 1 = RHS Hence PROVED |
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