1.

Show that tan 48' tan 16 tan42 tan 74=1​

Answer»

Answer:

given:-

LHS=TAN 48 tan 16 tan42 tan 74

tan48 tan16 tan(90-42) tan(90-74)

tan48 tan16 cot48 cot16 (SINCE tan(90-Ø) = cotØ)

tan48cot48 tan16cot16

1×1 (since tanØcotØ = 1)

1 = RHS

Hence PROVED



Discussion

No Comment Found

Related InterviewSolutions