Show that [square root of 2+3 square root of 8]^2 = 98

1.	Show that [square root of 2+3 square root of 8]^2 = 98
Answer» ANSWER: $( \sqrt{2} + 3 \sqrt{8} ) {}^{2} = ( \sqrt{2} + 6 \sqrt{2} ) {}^{2} =$ $(7 \sqrt{2} ) {}^{2} = 49 \times 2 = 98$

Answer»

ANSWER:

$( \sqrt{2} + 3 \sqrt{8} ) {}^{2} = ( \sqrt{2} + 6 \sqrt{2} ) {}^{2} =$

$(7 \sqrt{2} ) {}^{2} = 49 \times 2 = 98$

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Show that [square root of 2+3 square root of 8]^2 = 98

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