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Show that sin(50° + θ) – cos (40° – θ) = 0. |
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Answer» LHS = sin (50° + θ) – cos (40° - θ) We know that, Sin A = cos (90° - A) Here, A = 50° + θ ⇒ cos {90° -( 50° + θ)} – cos (40° - θ) ⇒ cos (40° - θ) – cos (40° - θ) = 0 = RHS Hence Proved |
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