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Show that n(m2-1)=2m, I m= sin theta + cos theta and n= sec theta+ cosec theta |
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Answer» Answer: 2m (theta=θ) Step-by-step EXPLANATION: sin theta + COS theta= m, SEC theta + cosec theta = N. Consider LHS n(m^2 - 1)n(m 2 −1) (sec\theta + cosec\theta)[(cos\theta + sin\theta)^2 - 1](secθ+cosecθ)[(cosθ+sinθ) 2 −1] (sec\theta + cosec\theta)[cos^2 \theta + sin^2 \theta + 2sin\theta cos\theta-1] (secθ+cosecθ)[cos 2 θ+sin 2 θ+2sinθcosθ−1] sec\theta 2sin\theta cos\theta + cosec\theta . 2sin\theta cos\thetasecθ.2sinθcosθ+cosecθ.2sinθcosθ 2sin\theta + 2 cos\theta2sinθ+2cosθ 2[sin\theta + cos\theta]2[sinθ+cosθ] = 2m PLEASE MARK ME AS THE BRAINIEST!!! |
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