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Show that lines represented by 3x2 – 4xy – 3y2 = 0 are perpendicular to each other. |
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Answer» Comparing the equation 3x2 – 4 xy – 3y2 = 0 with ax2 + 2hxy + by2 = 0, we get, a = 3, 2h = -4, b = -3 Since a + b = 3 + (-3) = 0, the lines represented by 3x2 – 4xy – 3y2 = 0 are perpendicular to each other. |
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