Saved Bookmarks
| 1. |
Show that \left| \begin{array}{ccc}{y+z} & {x} & {x} \\ {y} & {z+x} & {y} \\ {z} & {z} & {x+y}\end{array}\right|=4 x y z |
|
Answer» (y+z)(x^2+xz+yz+xy-yz)-x(xy+y^2-yz)+x(yz-z^2-xz)=x^2y+x^2z+xyz+xz^2+xy^2+xyz-x^2y-xy^2+xyz+xyz-xz^2-x^2z=4xyz |
|