Show that: (i) 1−sin 60∘cos 60∘=tan 60∘−1tan 60∘+1

1.	Show that: (i) 1−sin 60∘cos 60∘=tan 60∘−1tan 60∘+1 (ii) cos 30∘+sin 60∘1+sin 30∘+cos 60∘=cos 30∘
Answer» Show that: (i) $\frac{1 - sin 60^{\circ}}{cos 60^{\circ}} = \frac{tan 60^{\circ} - 1}{tan 60^{\circ} + 1}$ (ii) $\frac{cos 30^{\circ} + sin 60^{\circ}}{1 + sin 30^{\circ} + cos 60^{\circ}} = cos 30^{\circ}$

Show that: (i) 1−sin 60∘cos 60∘=tan 60∘−1tan 60∘+1 (ii) cos 30∘+sin 60∘1+sin 30∘+cos 60∘=cos 30∘

Answer»

Show that:

(i) $\frac{1 - sin 60^{\circ}}{cos 60^{\circ}} = \frac{tan 60^{\circ} - 1}{tan 60^{\circ} + 1}$

(ii) $\frac{cos 30^{\circ} + sin 60^{\circ}}{1 + sin 30^{\circ} + cos 60^{\circ}} = cos 30^{\circ}$

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Show that: (i) 1−sin 60∘cos 60∘=tan 60∘−1tan 60∘+1 (ii) cos 30∘+sin 60∘1+sin 30∘+cos 60∘=cos 30∘

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