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| 1. |
Show that for any set A and B,A=(A intersection B) union (A-B) and A union (B-A) = (A union B) |
| Answer» We have(A intersection B)union(A intersection B\') ,since( A -- B)=A intersection B\'.==>A intersection (B union B\'), by distributive law .==>A intersection U ,as B union B\'=U(union set).==>A.Also,we have A union (B -- A)==>A union (B intersection A\')==>(A union B ) intersection (A union A\')==>(A union B) intersection U ,since A union A\'=U==>A union B | |