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Show that every positive odd integer is of the form 6n+1 , 6n+3, 6n+5. |
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Answer» (1).........a=bq+r a=6q+6 2 (3q) a=6q+2 (2)........a=2 (3q+1) a=6q+4 (3)........a=6q+r a=2 (3q+2) those number DIVISIBLE by 2 so,that no will be positive number |
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