Show that dot product of two equal vectors is equal to square of magni

1.	Show that dot product of two equal vectors is equal to square of magnitude of either of them.
Answer» ANSWER: Dot product of two VECTORS a and b is given by: a.b=\|a\|\|b\|cosФ In this case as both the vectors are EQUAL the MAGNITUDE of a=b and the ANGLE between them is 0 a.b=\|a\|\|a\|cos0 cos0=1 therefore a.b=a.a=\|a\|² Hence proved.

Show that dot product of two equal vectors is equal to square of magnitude of either of them.

Answer»

ANSWER:

Dot product of two VECTORS a and b is given by:

a.b=|a||b|cosФ

In this case as both the vectors are EQUAL the MAGNITUDE of a=b and the ANGLE between them is 0

a.b=|a||a|cos0

cos0=1

therefore a.b=a.a=|a|²

Hence proved.

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Show that dot product of two equal vectors is equal to square of magnitude of either of them.

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