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Show that cos4x=1-sin²x.cos²x |
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Answer» 8 is missing Yes LHS :cos4x=cos2(2x)=1−2sin22x=1−2(sin2x)2=1−2(2sinxcosx)2=1−8sin2xcos2x\xa0= RHS cos4x=1-sin²x.cos²x here 8 is missing I thought |
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