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Show that cos2(45° + θ) + cos2(45°-0)tan (60° + θ) tan (30°-0). |
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Answer» cos^2(45 + theta) + sin^2{90 - (45 -theta)} = tan(60 + theta) cot{90 - (30 - theta)} cos^2(45 + theta) + sin^2(90 - 45 + theta) = tan(60 + theta) cot(90 - 30 + theta) =cos^2(45 + theta) + sin^2(45 + theta) = tan(60 + theta) cot(60 + theta) 1=1 |
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