1.

Show that C0 + C1 + C2 + …… + C9 = 512

Answer»

Since C0 + C1 + C2 + C3 + ….. + Cn = 2n

Putting n = 9, we get

C0 + C1 + C2 + ….. + C9 = 29

∴ C0 + C1 + C2 + …… + C9 = 512



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