1.

Show that any positive odd integer is of form of (6m+1) or (6m+3) or (6m+5) where m is some integer.​

Answer»

Step-by-step explanation:

If the no is of form n=6m+r then r can be 0 1 2 3 4 or 5

but since it's an ODD no

when n = 6m = 2(3M)= EVEN (contradiction)

when n = 6m + 2 = 2(6m+1) = even (contradiction)

when n - 6m + 4= 2(3m + 2) = even (contradiction yet again)

so the only forms it can be are 6m+1, 6m+3, 6m+5

Hope this helps!!



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