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Show that any positive odd integer is of form of (6m+1) or (6m+3) or (6m+5) where m is some integer. |
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Answer» Step-by-step explanation: If the no is of form n=6m+r then r can be 0 1 2 3 4 or 5 but since it's an ODD no when n = 6m = 2(3M)= EVEN (contradiction) when n = 6m + 2 = 2(6m+1) = even (contradiction) when n - 6m + 4= 2(3m + 2) = even (contradiction yet again) so the only forms it can be are 6m+1, 6m+3, 6m+5 Hope this helps!! |
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