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Show that any positive integer is form of 4q+1or4q+3, where q is some integer |
Answer» Question should be:ANSWER:
GIVEN:
TO PROVE:
SOLUTION:LET n be any positive integer which is divided by 4 we GET some quotient 'q' and remainder 'r' => n = 4q+r. .....(i) Where r = 0, 1 ,2 ,3 Putting r = 0 in eq(i) => n = 4q (Which is even) Putting r = 1 => n = 4q+1. (Which is odd) Putting r = 2 => n = 2(2q+1) ..(which is even) Putting r = 3 => n = 4q+3 (which is odd) Here any odd positive integer is in the form of 4q+1 , 4q+3 for some positive integer q. |
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