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Show that an ideal inductor does not dissipate power in an ac circuit. |
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Answer» SOLUTION :We know that average power consumed in an a.c. circuit is given as : `P_(av)=V_(rms) cos PHI` where `phi=` phase difference between instantaneous VALUES of voltage and current. For an ideal inductor current lags behind the voltage by `(pi)/(2)` . As `phi = (pi)/(2)` , so cos `phi` and CONSEQUENTLY the average power `P_(av)=V_(rms)xxI_(rms)xxcos""(pi)/(2)` =0 . So an ideal inductor does not dissipate power in an a.c. circuit. |
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