Show that (a ,a ) (-a,-a ) ( √3a, √3a ) are vertices of an equilat

1.	Show that (a ,a ) (-a,-a ) ( √3a, √3a ) are vertices of an equilateraltriangle.
Answer» Step-by-step explanation: a(a,a) b(-a,-a) c(√3a,√3a) m(AB)=y2-y1/x2-x1 = -a-a/-a-a = -2a/-2a =1 m(bc)=y2-y1/x2-x1 = √3a+a/√3a+a =1 m(AC)=y2-y1/x2-x1 = √3a-a/√3a-a =1 therefore it is an equilateral TRIANGLE

Show that (a ,a ) (-a,-a ) ( √3a, √3a ) are vertices of an equilateraltriangle.

Answer»

Step-by-step explanation:

a(a,a)

b(-a,-a)

c(√3a,√3a)

m(AB)=y2-y1/x2-x1

= -a-a/-a-a

= -2a/-2a

m(bc)=y2-y1/x2-x1

= √3a+a/√3a+a

m(AC)=y2-y1/x2-x1

= √3a-a/√3a-a

therefore it is an equilateral TRIANGLE

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Show that (a ,a ) (-a,-a ) ( √3a, √3a ) are vertices of an equilateraltriangle.

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