1.

Show that A(6,4)B(5,_2)C(7,_2) are the vertices of an isosceles ?

Answer»

ANSWER:

the vertices of TRIANGLE is A(6,4),B(5,-2),C(7,-2)

Using distance FORMULA:

√(x2-x1)^2+(y2-y1)^2

AB=√(5-6)^2+(-2-4)^2

=√1^2+(-6)^2

=√1+36

=√37 units

AC=√(7-6)^2+(-2-4)^2

=√1^2+(-6)^2

=√1+36

=√37 units

therefore AB=AC

therefore ∆ABC is an isosceles triangle

Hope this help you..


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