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Show that √(75+12√21) = 3√7+2√3, dot square on both sides apply operations only on the left hand side. |
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Answer» To Find : Show that its Equal Solution: Let SAY √(75+12√21) = 3√7+2√3 = A LHS = √(75+12√21) = A RHS = 3√7+2√3 = A Squaring both sides => (3√7+2√3 )² = A² => (3√7)² + (2√3)² + 2*3√7*2√3 = A² => 63 + 12 + 12√21 = A² => 75 + 12√21 =A² Taking square ROOT on both sids => √(75+12√21) = A Hence LHS = RHS = √(75+12√21) QED proved Learn more: What is the square root of 16 +6√7 is - Brainly.in find the square root of(1+i)2 - Brainly.in |
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