1.

Show that 3V2 is irrational.

Answer»

Let us assume that 3√2 is rational

ie,3√2=a/bwhere a and b are co-prime numbers

√2=(a/b)(1/3)=a/3bHere √2 is irrational and a/3b is rational

Thus our assumption is wronghence 3√2 is irrational



Discussion

No Comment Found