Show that 3+2√5 is irrational number

1.	Show that 3+2√5 is irrational number
Answer» $\huge\mathtt{{\fcolorbox{gold}{gold}{Answer!~~~~~~(~:}}}$ $\small\bold{ }$ LET US ASSUME that $\large\mathsf{3+2{\sqrt{5}}}$ is rational... Then we get, $\large\mathsf{3+2{\sqrt{5}}={\frac{p}{q}}}$ , Where, p and q are integers, and q≠0 $\large\implies\mathsf{2{\sqrt{5}}={\frac{p}{q}}-3={\frac{p-3q}{q}}}$ Here, LHS $\large\mathsf{{\sqrt{5}}}$ is irrational, where as RHS represents a rational number. Thus LHS≠RHS $\large\implies$ our assumption is wrong, $\large\mathsf{3+2{\sqrt{5}}}$ is not rational, it is irrational... $\small\bold{ }$ $\large\bold{{\underline{\underline{\blue{Be \ Brainly!}}}}}$ $\huge\bold\orange{{\underline{\overline{Brainliest \ Please!}}}}$

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