show that (1/x^a-b)^1/a-c × (1/x^b-c)^1/b-c × (1/x^c-a)^1/c-b = 1 where a not equal to b not equal to c

show that (1/x^a-b)^1/a-c × (1/x^b-c)^1/b-c × (1/x^c-a)^1/c-b = 1 wh

1.	show that (1/x^a-b)^1/a-c × (1/x^b-c)^1/b-c × (1/x^c-a)^1/c-b = 1 where a not equal to b not equal to c
Answer» Plz check UR ques. I think little correction NEEDED..

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show that (1/x^a-b)^1/a-c × (1/x^b-c)^1/b-c × (1/x^c-a)^1/c-b = 1 where a not equal to b not equal to c

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