1.

Show that,`(1+5^(-1))(1+5^(-2))(1+5^(-4))(1+5^(-8))"....."(1+5^(-2n))=(5)/(4)(1-5^(-2(n+1)))`.

Answer» `LHS=(1+5^(-1))(1+5^(-2))(1+5^(-4))(1+5^(-8))"....."(1+5^(-2n))`
`=(1+(1)/(5))(1+(1)/(5^(2)))(1+(1)/(5^(4)))"......."(1+(1)/(5^(2n)))`
`=((1-(1)/(5)))/((1-(1)/(5)))(1+(1)/(5))(1+(1)/(5^(2)))(1+(1)/(5^(4)))"......."(1+(1)/(5^(2n)))`
`=(5)/(4)[(1+(1)/(5^(2)))(1+(1)/(5^(2)))(1+(1)/(5^(4)))"......."(1+(1)/(5^(2n)))]`
`" " vdots " " vdots " "vdots" "`
`=(5)/(4)(1-(1)/(5^(2^(n+1))))=(5)/(4)(1-5^(2^(n+1)))=RHS`.


Discussion

No Comment Found

Related InterviewSolutions