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Shanti Sweets Stall was placing an order for making cardboard boxes for packing their sweets. Two sizes of boxes were required. The bigger of dimensions 25 cm × 20 cm × 5 cm and the smaller of dimensions 15 cm × 12 cm × 5 cm. For all the overlaps, 5% of the total surface area is required extra. If the cost of the cardboard is Rs. 4 for 1000 cm2, find the cost of cardboard required for supplying 300 boxes of each kind. |
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Answer» Given:- The bigger of dimensions 25 cm× 20 cm× 5 cm and the smaller dimensions 15 cm× 12 cm×5cm. all the overlaps, 5% of TOTAL surface area is REQUIRED extra. the cost of cardboard is rs 4 for 1000 cm square. To FIND:- Find the cost of cardboard required for supplying 250 boxes of each kind. Solutions:- Length of bigger box = 25cm Breadth of bigger box = 20cm Height of bigger box = 5cm Total surface area bigger box = 2(lb + bh + hl) = 2(25 × 20 + 20 × 5 + 5 × 25) = 2(500 + 100 + 125) = 2 × 725 = 1450cm² Extra area required for overlapping = 1450 × 5 / 100 = 1450/20 = 72.5cm² While considering all overlaps total of 1 bigger box. = 1450 + 72.5 = 1522.5cm² Area of cardboard sheet required for 250 such bigger boxes. = 1522.5 × 250 = 380625cm² Total surface area of smaller box. = 2(15 × 12 + 15 × 5 + 12 × 5) = 2(180 + 75 + 60) = 2 × 315 = 630 Therefore, Extre area of required for overlapping. = 630 × 5 / 100 = 63/2 = 31.5cm² Total surface area of 1 smaller box while considering all overlaps. = 630 + 31.5 = 661.5cm² Area of cardboard sheet required for 250 smaller boxes. = 250 × 661.5 = 165375cm² Total cardboard sheet required = 380632 + 165375 = 546000cm² Cost of 1000cm² cardboard sheet = Rs 4. Cast of 546000cm² cardboard sheet. = Rs (546000/1000 × 4) = Rs 546 × 4 = Rs 2184 Hence, the cost of cardboard sheet required for 250 such boxes of each will be Rs 2184. |
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