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Seven different coins are to be divided amongst three persons. If no two of the persons receive the samenumber of coins but each receives at least one coin & none is left over, then the number of ways in whichthe division can be made is |
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Answer» Well with three people and no two people getting the same number (and everyone gets at least 1)- the only way is to divide it is 1-2-4,,, Assume person one gets one coin... there are 7 possibilitiesPerson two gets 2 coins from the remaining 6 = 6!/(6-2)!2!=15 (because the order of the coins doesn't matter)Person 3 gets what's left - 4 coins (1 possibility again order does not matter) but there are also 6 ways to arrange the people...7*15*6=630 |
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