Saved Bookmarks
| 1. |
∫sen xdx√sin (2x+A)+sinA=∫sec xdx√2 sin x cosx+(2cos2x−1)sin A+sinA=∫sec x dx√2 cos x sin (x+A)\ |
|
Answer» ∫sen xdx√sin (2x+A)+sinA=∫sec xdx√2 sin x cosx+(2cos2x−1)sin A+sinA=∫sec x dx√2 cos x sin (x+A)\ |
|