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∫secx(2+secx)(1+2secx)2dx=f(x)+c, where C is constant of integration and f(0) = 0, then ∫π0f(x)dx is equal to |
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Answer» ∫secx(2+secx)(1+2secx)2dx=f(x)+c, where C is constant of integration and f(0) = 0, then ∫π0f(x)dx is equal to |
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