1.

SECTIONWhat is the value of cos 67Sin 2

Answer»

cos^2 67 - sin^2 23

= cos^2 67 - (cos^2 (90-23))

= cos^2 67 - cos^2 67

= 0

cos² 67°-sin ²23°=cos² 67°-sin² (90°-67°)since cos(90°-A)=sin Acos² 67°-sin ²23°=cos ²67°-cos ²67°=0



Discussion

No Comment Found