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Section-CIf the distance between points (x, 3) and (5, 7) is 5, then find the value of x.Or |
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Answer» ong>Step-by-step explanation:
\begin{gathered} AB = \sqrt{ (5-x)^{2} + (7-3)^{2}} \\= \sqrt{ 5^{2} + x^{2} - 2 \times 5 \times x + 4^{2} } \\=\sqrt{ 25 + x^{2} - 10X + 16} \\= \sqrt{x^{2} - 10x + 41} \end{gathered} AB= (5−x) 2 +(7−3) 2
= 5 2 +x 2 −2×5×x+4 2
= 25+x 2 −10x+16
= x 2 −10x+41
\begin{gathered} \red { Distance \: between \:points\: (x,3)\: and\: (5,7) }\\\green { = \sqrt{x^{2} - 10x + 41}} \end{gathered} Distancebetweenpoints(x,3)and(5,7) = x 2 −10x+41
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