1.

Sece + tano)=p Then find sec e-tang:

Answer»

Given secA + tan A = pRecall the identity, sec^2A – tan^2A = 1⇒ (secA + tan A)(secA – tanA) = 1⇒ p × (secA – tanA) = 1∴ (secA – tanA) = 1/p



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