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- SecB न सवारी |
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Answer» SecA+tanA=p ----------------------------(1)∵, sec²A-tan²A=1or, (secA+tanA)(secA-tanA)=1or, secA-tanA=1/p -----------------------(2)Subtracting (2) from (1) we get,2tanA=p-1/por, tanA=(p²-1)/2p∴, cotA=2p/(p²-1)Now, cosec²A-cot²A=1or, cosec²A=1+cot²Aor, cosec²A=1+{2p/(p²-1)}²or, cosec²A=1+4p²/(p²-1)²or, cosec²A=(p⁴-2p²+1+4p²)/(p²-1)²or, cosec²A=(p⁴+2p²+1)/(p²-1)²or, cosec²A=(p²+1)²/(p²-1)²or, cosecA=(p²+1)/(p²-1) |
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