1.

SecA-TanA=x then+find+SecA+TanA=?

Answer»

ANSWER:

we know that sec^2A-tan^2A=1

we also know that a^2-b^2=(a+b)(a-b)

so,(secA+tanA)(secA-tanA)=1

x(secA+tanA)=1

secA+tanA=1/x



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