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(secA+tanA)(1-sinA)= |
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Answer» (secA+tanA)(1-sinA) =( 1/COS A+sinA/cosA)(1-sinA) =( 1+sin A/cosA)(1-sinA) = 1-sin²A/cosA = cos²A/cosA = cos A hᎾᏢᎬ ᎥᏆ hᎬᏞᏢs |
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