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SecA(1-sinA) (secA+tanA)=1 |
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Answer» Answer: secA (1-sinA) (secA + tan A) = (secA-sinA×secA)(secA+tanA) =(secA-tanA) (secA+tanA) as secA=1/cosA and sinA/cosA=tanA = (sec²A-tan²A) as (a+b)(a-b)=a²-b² =sec²A-tan²A=1 from identity. Hence PROVED. |
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