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seca-1/seca+1=sin2a/(1+cosa)2=cosec theta sec theta-1/cosec theta +sec theta |
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Answer» (secA – 1)/ (sec A + 1) (1/cosA - 1)/ (1/cos A +1) (1 – cosA/cosA)/ (1 + cosA/cosA) (1 – cosA)/ (1 + cosA) Multiplying numerator and denominator by (1 + cosA), we get (1 - cosA)(1 + cosA)/ (1 + cosA)2 (1 – cos^2A)/ (1 + cosA)^2 Sin^2A/ (1 + cosA)^2 [sinA/(1 + cosA)]^2= R.H.S Hence proved |
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