Sec θ – tan θ)² = ??? – InterviewSolution

1.	Sec θ – tan θ)² = ???
Answer» ${( \sec( \alpha ) - \tan( \alpha ) })^{2} \\ \\ { \sec( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + { \tan( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + 2 { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\$

Sec θ – tan θ)² = ???

Answer»

${( \sec( \alpha ) - \tan( \alpha ) })^{2} \\ \\ { \sec( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + { \tan( \alpha ) }^{2} + { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\ 1 + 2 { \tan( \alpha ) }^{2} - 2 \sec( \alpha ) \tan( \alpha ) \\ \\$

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Sec θ – tan θ)² = ???​

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Sec θ – tan θ)² = ???