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Sec^4A- sec^2A = tan^2A +tan^4A |
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Answer» ong>Answer -- GIVEN ⇒
LHS = tan⁴A+tan²A
= (tan²A)²+tan²A
= tan²A(tan²A+1)
= tan²Asec²A
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*/ By TRIGONOMETRIC identity:
1+tan²A = sec²A
Or
tan²A = sec²A-1*/
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= (sec²A-1)sec²A
= sec⁴A-sec²A
= RHS
tan⁴A+tan²A = sec⁴A-sec²A Hope it heelps you .... XD |
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