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Sec 4 theta - sec 2 theta = tan 4 theta +tan 2 theta . Please answer it right now

Answer» L.H.S.sec4θ - sec2θ= sec2\xa0θ [ sec2\xa0θ - 1 ] { taking sec2\xa0θ\xa0as common }= sec2θ . tan2θ\xa0R.H.S.tan4θ +tan2θ=tan2θ [ tan2θ + 1 ]= tan2θ . sec2θ=> L.H.S. = R.H.S.


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