SBBDete:Page No. :

1.	SBBDete:Page No. :
Answer» Given quadratic equation: 100x²-20x+1=0 => (10x)² -2(10x)+1² = 0 => (10x-1)² = 0 / By algebraic identity a²-2ab+b² = (a-b)² */ => 10x-1 = 0 or 10x-1 = 0 => 10x = 1 or 10x = 1 => x = 1/10 or x = 1/10 [ equal roots ] Therefore, 1/10, 1/10 are two roots of given Quadratic equation. 100x^2 -20x +1=0100x^2-10x-10x+1=010x(10x-1)-(10x-1)=0(10x-1)(10x-1)=0either 10x-1=0, x= 1/10or 10x-1=0, x= 1/10 100x² - 20x + 1 = 0100x² - 10x - 10x + 1 = 010x(10x - 1) -1(10x - 1) = 0(10x - 1) (10x - 1) = 0x =1/10 , x = 1/10 PLEASE LIKE AND ACCEPT AS BEST ANSWER (10x-1) (10x-1) =0x=1/10 is answer

Answer»

Given quadratic equation:

100x²-20x+1=0

=> (10x)² -2*(10x)+1² = 0

=> (10x-1)² = 0

/* By algebraic identity

a²-2ab+b² = (a-b)² */

=> 10x-1 = 0 or 10x-1 = 0

=> 10x = 1 or 10x = 1

=> x = 1/10 or x = 1/10

[ equal roots ]

Therefore,

1/10, 1/10 are two roots of given Quadratic equation.

100x^2 -20x +1=0100x^2-10x-10x+1=010x(10x-1)-(10x-1)=0(10x-1)(10x-1)=0either 10x-1=0, x= 1/10or 10x-1=0, x= 1/10

100x² - 20x + 1 = 0100x² - 10x - 10x + 1 = 010x(10x - 1) -1(10x - 1) = 0(10x - 1) (10x - 1) = 0x =1/10 , x = 1/10

PLEASE LIKE AND ACCEPT AS BEST ANSWER

(10x-1) (10x-1) =0x=1/10 is answer

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