1.

SARIf SV = 3b – 15 andUV = 4b - 25, findthe value of b, inrectangle RSTU.VTU​

Answer»

ANSWER:

(3a+4b)×(4a+3b)

3a(4a+3b)+4b(4a+3b)

⇒12a  

2

+9ab+16ab+12b  

2

 

⇒12a  

2

+25ab+12b  

2

 

⇒12[a  

2

+b  

2

−2ab]+ab

=12[a+b]  

2

+ab

Step-by-step explanation:



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