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SARIf SV = 3b – 15 andUV = 4b - 25, findthe value of b, inrectangle RSTU.VTU |
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Answer» (3a+4b)×(4a+3b) 3a(4a+3b)+4b(4a+3b) ⇒12a +9ab+16ab+12b 2
⇒12a 2 +25ab+12b 2
⇒12[a 2 +b 2 −2ab]+ab =12[a+b] 2 +ab Step-by-step explanation: |
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