Sanya has a piece of land which is in the shape of a Rhombus. Shewants

1.	Sanya has a piece of land which is in the shape of a Rhombus. Shewants to divide it equally in to two parts one for her son and other forher daughter.If the perimeter of the land is 400 m and one of its diagonalis 160m27.Find How much area eÄch of them will get?
Answer» As the diagonals of rhombus bisect each other: Therefore OD = 1/2.BD = 1/2 x 160 = 80 m OC = 1/2.AC In△OCD, we have, CD^2= OC^2+ OD^2 100^2 =OC^2+ 80^2 ⇒ OC^2= 10000 - 6400 ⇒OC^2 = 3600⇒OC = 60 m Therefore, area of△BCD = 1/2(BD x OC) = 1/2 x 160 x 60 = 4800 m2 ∴Each of them will get 4800 m2of area for their crops.

Sanya has a piece of land which is in the shape of a Rhombus. Shewants to divide it equally in to two parts one for her son and other forher daughter.If the perimeter of the land is 400 m and one of its diagonalis 160m27.Find How much area eÄch of them will get?

Answer»

As the diagonals of rhombus bisect each other: Therefore

OD = 1/2.BD = 1/2 x 160 = 80 m

OC = 1/2.AC

In△OCD, we have,

CD^2= OC^2+ OD^2

100^2 =OC^2+ 80^2 ⇒ OC^2= 10000 - 6400

⇒OC^2 = 3600⇒OC = 60 m

Therefore, area of△BCD = 1/2(BD x OC) = 1/2 x 160 x 60 = 4800 m2

∴Each of them will get 4800 m2of area for their crops.