1.

Sand drops from a stationary hopper at the rule of 5kg s^(1) onto a conveyor belt moving with a constant speed of 2ms^(-1). What is the force required to keep the belt moving and what is the power delivered by the motor moving the belt?

Answer»

Solution :Impulse J= Ft`-mv, F= (mv)/(t)`
`v=2 MS^(-1), (m)/(t)= 5kgs^(-1) rArr F= 10N`
POWER `P= (W)/(t)= (FS)/(t) = Fv`
`=10 xx 2 = 20` watt


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