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Sand drops from a stationary hopper at the rule of 5kg s^(1) onto a conveyor belt moving with a constant speed of 2ms^(-1). What is the force required to keep the belt moving and what is the power delivered by the motor moving the belt? |
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Answer» Solution :Impulse J= Ft`-mv, F= (mv)/(t)` `v=2 MS^(-1), (m)/(t)= 5kgs^(-1) rArr F= 10N` POWER `P= (W)/(t)= (FS)/(t) = Fv` `=10 xx 2 = 20` watt |
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