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`S_(N)1` reaction underoges through carbocation intermediate as follows: `R-X(aq.) overset("Slow") hArr R^(+)(aq.)+` `X^(-) (aq.) underset ("fast") overset(H_(2)O)to ROH(aq.)+H^(+)(aq.)` [R=t-Bu, iso-Pr, Me] `(X=Cl, Br, I)` The correct statements are I. The decreasing order of rate of `S_(N)1` reaction is `t-BuXgtiso-PrXgtEtXgtMeX` II. The decreasing order of ionisation energy is `MeXgtEtXgtiso-PrXgt t-BuX` III. The decreasing order of energy of activation is `t-BuX gt iso- PrXgtEtXgtMeX`A. I & II are correctB. I & III are correctC. II and III are correctD. I,II & III are correct |
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Answer» Correct Answer - A Rate of `S_(N)1` reaction is a `tBuXgriso-PrXgtEtXgtMeX` So order of activation energy `t-BuXltiso-PrXltEtXltMeX` order of ionisation energy ltrbgt `tBuXltiso-PrxltEtXltMeX` |
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