S 20 m Rnd ala18 m25 mb. T10 m – InterviewSolution

1.

S 20 m Rnd ala18 m25 mb. T10 m

Answer»

area of the upper part ( SRTQ) which is a trapezium ,will be 1/2 *( 20+25)* 18 = 405 m²

area of lower part (TQP) which is a triangle ,will be 1/2 * 25 * 10 = 125 m²

So, the area will be (405+125) m² = 530 m²

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