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Rupees 9000 for 2 years 4 months at 10% per annum compounded annually

Answer»

Given Principal Amount= P= 9000

Rates of INTEREST Per annum= i =10%

TIME= n =2YEARS 4 MONTHS.. or 2 1/3 years

Compound Interest = P[ (1+i)^n - 1]

=9000[ (1+10/100)^2 1/3 - 1]

=9000[(1 + 10/100)^2 (1+ 10/100×3) -1]

=9000[ (1.1)^2 (1.033) - 1]

=9000[1.21 × 1.033 - 1]

=9000[1.25033333293 - 1]

=9000[ 0.25033333293]
= 2253 is the Compound Interest...

Then compounded Amount = Principal Amount + Compound Interest

=9000+ 2253= 11253 is the Compounded amount



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