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Root of the equation x^2 +(2p-1)x +p=0 are real if |
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Answer» Step-by-step explanation: let the root of the equation be REAL then b²-2ac=0 so we will apply this in the GIVEN equation. (2p-1)²-2×1×p=0 4p²+1-4p-2p=0 4p²-6p+1=0 |
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