1.

Root of the equation x^2 +(2p-1)x +p=0 are real if​

Answer»

Step-by-step explanation:

let the root of the equation be REAL then

b²-2ac=0

so we will apply this in the GIVEN equation.

(2p-1)²-2×1×p=0

4p²+1-4p-2p=0

4p²-6p+1=0

using the quadratic FORMULA we can FIND the VALUE of p.



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